10a^2+9a=159

Solution for 10a^2+9a=159 equation:

10a^2+9a=159

We move all terms to the left:

10a^2+9a-(159)=0

a = 10; b = 9; c = -159;
Δ = b2-4ac
Δ = 92-4·10·(-159)
Δ = 6441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{6441}}{2*10}=\frac{-9-\sqrt{6441}}{20}
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{6441}}{2*10}=\frac{-9+\sqrt{6441}}{20}
$